Project like below
server
├── celery.py
├── tasks.py
tasks.py
from __future__ import absolute_import, unicode_literals
from sys import path
from .celery import app_celery
from time import sleep
@app_celery.task
def my_func():
sleep(5)
print("Process finished")
celery.py
from __future__ import absolute_import, unicode_literals
from celery import Celery
app_celery = Celery('server',
broker='redis://',
backend='redis://',
include=['server.tasks'])
app_celery.conf.update(
result_expires=3600,
)
if __name__ == '__main__':
app_celery.start()
celery -A server worker -l info
starts well, make a test like below and it was perfect
$ ipython
Python 3.7.4 (default, Aug 13 2019, 20:35:49)
Type 'copyright', 'credits' or 'license' for more information
IPython 7.8.0 -- An enhanced Interactive Python. Type '?' for help.
In [1]: from server.tasks import my_func
In [2]: my_func.delay()
Out[2]: <AsyncResult: 39a21329-0e80-4f6e-ac08-536832414756>
I want to add a script test.py
under server
test.py
from tasks import my_func
my_func.delay()
When I run python test.py
under server
, it reports
Traceback (most recent call last):
File "test.py", line 2, in <module>
from tasks import my_func
File "/xxx/server/tasks.py", line 3, in <module>
from .celery import app_celery
ImportError: attempted relative import with no known parent package
Add a __init__.py
file inside your server directory. This file can be empty.
Python only allows relative imports in regular packages. A regular package is defined as a directory that contains a __init__.py
file.
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.