Hey look here i am trying to get result from these three select statements at once but i am noit able to do so. So please help me in rectifying my mistake. Don't rate me negative if you found my english or question method bad.
$sql = $conn->prepare("SELECT Count(c.c_id) from complaints c, users u,cell_num cn where c.status=? AND c.u_id_fk=u.u_id AND u.u_id=cn.u_id_fk");
$sql->bind_param("i",$statOpen);
$sql .= $conn->prepare("SELECT Count(c.c_id) from complaints c, users u,cell_num cn where c.status=? AND c.u_id_fk=u.u_id AND u.u_id=cn.u_id_fk");
sql->bind_param("i",$statProgress);
$sql .= $conn->prepare("SELECT Count(c.c_id) from complaints c, users u,cell_num cn where c.status=? AND c.u_id_fk=u.u_id AND u.u_id=cn.u_id_fk");
$sql->bind_param("i",$statClosed);
$sql->execute();
$sql->store_result();
if($sql->num_rows > 0)
{
$sql->bind_result($c_id);
while( $sql->fetch() )
{
$user[] = array(
'c_id'=>$c_id
);
}
echo json_encode($user);
$sql->close();
}
You can do conditional aggregation:
select
sum(c.status = ?) cnt_open,
sum(c.status = ?) cnt_progress,
sum(c.status = ?) cnt_closed
from complaints c
inner join users u on u.u_id = c.u_id_fk
inner join cell_num cn on cn.u_id_fk = u.u_id
This query accepts three parameters at once, that correspond to the three values that you were passing to your three individual queries.
Note that I modified the query to use standard joins (with the on
keyword) rather than old-school, implicit joins (with commas in the from
clause): this archaic syntax should not be used in new code.
You can make the query more efficient by adding a where
clause that filters on the three possible status
es (this requires passing each parameter twice):
where c.status in (?, ?, ?)
you can do so, it's more optimised
select c.statut,count(c.c_id)
from complaints c
inner join users u on u.u_id = c.u_id_fk
inner join cell_num cn on cn.u_id_fk = u.u_id
where c.status in (?, ?, ?)
group by c.status
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