Python: Raise exception but not from sub functions

Question

Is it possible in Python, to catch an exception at the current function level, but not from called sub functions?

Please consider this example:

def func(some_dict):
    print(some_dict["special_value"])

some_dict = {
    "general_value": True,
    # "special_value": True
}

try:
    if some_dict["general_value"]:
        func(some_dict)
except KeyError:
    print("General value not set")

I would like to catch the KeyError that if some_dict["general_value"]: might throw, but raise any KeyErrors from within func(...)

However, the example above will show General value not set although the key general_value is set.

I can think of the following workaround, but I'm wondering if there's a better way

temp_value = None

try:
    temp_value = some_dict["general_value"]
except KeyError:
    print("General value not set")

if temp_value: 
    func(some_dict)

Another way to ask this question: Is it possible to exclude certain parts within a try/except block from being caught?

Answer 1

Your workaround is the right general idea, but can be done more neatly as:

try:
    some_dict["general_value"]
except KeyError:
    print("General value not set")
else:
    func(some_dict)

or perhaps:

if "general_value" in some_dict:
    func(some_dict)
else:
    print("General value not set")

which seems a little clearer to me.

Answer 2

you could use a nested try/except - but this is not recommended.

try:
    if some_dict["general_value"]:
        try:
            func(some_dict)
        except KeyError:
            print("special error")
except KeyError:
    print("general value not set")