Accessing a list with only recursion and lambdas

Question

As part of my homework I have to access every element oa list without a for loop to use it in a function I'm allowed to use, eg:

myList=['Hello','World']

I've tried using lambda functions (Because I'm not allowed to declare functions with Def) but didn't work.

function(next(myList))

Also tried using next(myList) but sometimes the list can have 1000+ elements.

Answer 1

Use lambda with map for apply a function to each element:

myList=['Hello','World']

list(map(lambda x: x.upper(), myList))

Answer 2

Using map is the shortest way to do it. You don't need lambda.

li = list(range(10)) # this is your list
list(map(print, li)) # view each element

Answer 3

If you can use function you can use that trick

You can use recursion to access all elements.

At first create a function to read first element and delete that element.

Use that function again and again until the list is empty.

def show(my_list):
   try:
      print(my_list[0])
      del my_list[0]
      show(my_list)
   except:
      pass

Or if you want to do some action

new = []
def action(my_list):
   try:
      x = do_something(my_list[0])
      del my_list[0]
      new.append(x)
      action(my_list)
   except:
      pass

Here do_something(data) is your custom function.

Answer 4

I believe the cleanest way to do this is with a map function:

l = [1,2,3]
list(map(lambda x : print(x), l))
# returns
# >> 1
# >> 2
# >> 3