mongoose query to find based on multiple not equals

Question

i am trying to get results from my userId such that both type != 4 and userType != 1

i tried:

const transaction = {
    userId: userId,
    $and: [{ type: { $ne: 4 } }, { userType: { $ne: 1 } }]
  };
await.Transactions.find(transaction)

but this is giving me empty set.

the below is a snippet of my db data

id: 5ed8dfb1b6c73a69b0adca7d
amount: 150
userId: 5ed5c7fdc25ee07e41a502af
type: 4
userType: 1
recipientId: 5ed8d3a36b34b55f66f62fcd
status:"succeeded"

_id: 5ed987747833b724d9f31829
amount: 1000
userId: 5ed8d3a36b34b55f66f62fcd
type: 4
userType: 2
ChargeId: "tr_1GqSjvKYps1wFgvm0thxzh0p"
ChargeObject: "transfer"
status: "pending"
__v: 0

_id: 5ed987747833b724d9f31841
amount: 1000
userId: 5ed8d3a36b34b55f66f62fcd
type: 3
userType: 1
ChargeId: "ch_1GqSjvKYps1wFgvm0thxzh0p"
ChargeObject: "charge"
status: "pending"
__v: 0

Answer 1

based on your criteria, it should be like:

{ $and:[ {userId: userId},{ type: { $ne: 4 } }, { userType: { $ne: 1 } } ] }

Answer 2

The criteria are type != 4 and userType != 1 , if you want exclude documents for which both of these are true, this statement will be true for documents you want to match:

not(and(type != 4, userType != 1 ))

That seems to be some excessive negation, the above is logically equivalent to:

or(type = 4, userType = 1)

In MQL:

{userId: userId, $or:[ {type: 4}, {userType: 1} ]}