can typescript do union type assertion in this case? i want to use ab.a
or ab.b
or ab. hasOwnProperty
ab. hasOwnProperty
to do assertion of type A
or type B
? how do i do?
export interface A extends Object {
a: string;
}
export interface B extends Object {
b: number;
}
export type AorB = A | B;
function test(ab: AorB) {
// can ts auto predict this ?
if (ab.hasOwnProperty('a')) {
ab.a // type error
}
}
Update your function as below:
function test(ab: AorB) {
// can ts auto predict this ?
if ('a' in ab) {
console.log(ab.a);
}
}
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