Get last record of each ID

Question

I have this query:

SELECT  Truck.Name AS name,
        timestamp,
        oil,
        diesel,
        cargo,
        Truck.notes AS Remarks

        FROM trip
        INNER JOIN Truck USING (idTruck)
        WHERE idTruck IN('2','4','5','6','7','8','9','11','12','13','14','15','16')
        ORDER BY name, timestamp DESC

which returns ALL records from the ID's I was thinking of using CURDATE as

AND DATE(timestamp) = CURDATE()

in order to get last records but when a record is not modified a day (they usually do but sometimes this is not the case) I'm loosing the records. How would I modify the query to get the last entry of each idTruck regardless of the timestamp in a single query?

Answer 1

I suggest you use the MAX function of sql to get the last record ( MAX(Truck.Name) ):

SELECT  MAX(Truck.Name) AS name,
        timestamp,
        oil,
        diesel,
        cargo,
        Truck.notes AS Remarks

FROM trip
INNER JOIN Truck USING (idTruck)
WHERE idTruck IN('2','4','5','6','7','8','9','11','12','13','14','15','16')
ORDER BY name, timestamp DESC

To get the last record of each ID:

SELECT  MAX(Truck.Name) AS name,
        timestamp,
        oil,
        diesel,
        cargo,
        Truck.notes AS Remarks

FROM trip
INNER JOIN Truck USING (idTruck)
WHERE idTruck IN('2','4','5','6','7','8','9','11','12','13','14','15','16')
GROUP BY idTruck 
ORDER BY name, timestamp DESC

because according to sql.sh( https://sql.sh/fonctions/agregation/max ):

the aggregation function MAX() allows to return the maximum value of a column in a record set. The function can be applied to numeric or alphanumeric data. For example, it is possible to search for the most expensive product in a table in an online shop.