I'm trying to retrieve the url from an background image with Xpath or Javascript, but with no luck for now. this is what I have
<div style="width: 100%; display: inline-block;">
<div tws-article-images-preload="item" class="tws-article-images--preload ng-scope tws-article-images--
image-small" ng-click="closeImage()" use-original="useOriginal" style="background-image:
url("https://i.pinimg.com/originals/59/54/b4/5954b408c66525ad932faa693a647e3f.jpg;);">
</div>
</div>
And have tried this two with different modification
//*[starts-with(@style, 'background-image: url()] <--Did not work
return document.getElementsByClassName('tws-article-images--preload ng-scope tws-article-images--image-small').src
document.getElementsByClassName('classname')[0].style.backgroundImage.slice(4, -1).replace(/"/g, "");
You can try
return document.getElementsByClassName('tws-article-images--preload ng-scope tws-article-images--image-small').style.backgroundImage.slice(4, -1).replace(/["']/g, "");
Your XPath expression is wrong (missing '
and a possible annoying CRLF
). Fix it with:
//*[starts-with(@style, 'background-image:')]/@style
Then use regex to clean the result:
txt = 'background-image: url("https://i.pinimg.com/originals/59/54/b4/5954b408c66525ad932faa693a647e3f.jpg;);'
result = re.sub(r"^.+\"(.+?);.+", r"\1", txt)
print(result)
With XPath:
substring-after(substring-before(//*[starts-with(@style, 'background-image:')]/@style,';)'),'"')
Output: https://i.pinimg.com/originals/59/54/b4/5954b408c66525ad932faa693a647e3f.jpg
To retrieve the url from the background image you can usethe following solution:
Using slice()
:
var img = document.getElementsByClassName('tws-article-images--preload')[0], style = img.currentStyle || window.getComputedStyle(img, false), bgImage = style.backgroundImage.slice(4, -1).replace(/"/g, ""); //printing the url console.log('Image URL: ' + bgImage);
Using regex :
var img = document.getElementsByClassName('tws-article-images--preload')[0], style = img.currentStyle || window.getComputedStyle(img, false), var url = backgroundImage.match(/url\(["']?([^"']*)["']?\)/)[1]; //printing the url console.log('Image URL: ' + url);
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