How would I get the background-image
URL of a <div>
element in JavaScript? For example, I have this:
<div style="background-image:url('http://www.example.com/img.png');">...</div>
How would I get just the URL of the background-image
?
You can try this:
var img = document.getElementById('your_div_id'),
style = img.currentStyle || window.getComputedStyle(img, false),
bi = style.backgroundImage.slice(4, -1).replace(/"/g, "");
// Get the image id, style and the url from it var img = document.getElementById('testdiv'), style = img.currentStyle || window.getComputedStyle(img, false), bi = style.backgroundImage.slice(4, -1).replace(/"/g, ""); // Display the url to the user console.log('Image URL: ' + bi);
<div id="testdiv" style="background-image:url('http://placehold.it/200x200');"></div>
Edit:
Based on @Miguel and other comments below, you can try this to remove additional quotation marks if your browser (IE/FF/Chrome...) adds it to the url:
bi = style.backgroundImage.slice(4, -1).replace(/"/g, "");
and if it may includes single quotation, use: replace(/['"]/g, "")
Just to add to this in case anyone else has a similar idea, you could also use Regex:
var url = backgroundImage.match(/url\(["']?([^"']*)["']?\)/)[1];
However it seems like @Praveen's solution actually performs better in Safari and Firefox, according to jsPerf: http://jsperf.com/match-vs-slice-and-replace
If you want to account for cases where the value includes quotes but are unsure whether it's a double or single quote, you could do:
var url = backgroundImage.slice(4, -1).replace(/["']/g, "");
Try this:
var url = document.getElementById("divID").style.backgroundImage;
alert(url.substring(4, url.length-1));
Or, using replace
:
url.replace('url(','').replace(')','');
// Or...
backgroundImage.slice(4, -1).replace(/["']/g, "");
First of all you need to return your background-image content:
var img = $('#your_div_id').css('background-image');
This will return the URL as following:
"url(' http://www.example.com/img.png ')"
Then you need to remove the un-wanted parts of this URL:
img = img.replace(/(url\(|\)|")/g, '');
const regex = /background-image:url\\(["']?([^"']*)["']?\\)/gm; const str = `<div style="background-image:url('http://www.example.com/img.png');">...</div>`; let m; while ((m = regex.exec(str)) !== null) { // This is necessary to avoid infinite loops with zero-width matches if (m.index === regex.lastIndex) { regex.lastIndex++; } // The result can be accessed through the `m`-variable. m.forEach((match, groupIndex) => { console.log(`Found match, group ${groupIndex}: ${match}`); }); }
Log to console all background-image
URLs, without parentheses and quotes:
var element = document.getElementById('divId');
var prop = window.getComputedStyle(element).getPropertyValue('background-image');
var re = /url\((['"])?(.*?)\1\)/gi;
var matches;
while ((matches = re.exec(prop)) !== null) {
console.log(matches[2]);
}
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