I have a list of arrays, say
List = [A,B,C,D,E,...]
where each A,B,C etc. is an nxn array.
I wish to have the most efficient algorithm to find the unique nxn arrays in the list. That is, say if all entries of A and B are equal, then we discard one of them and generate the list
UniqueList = [A,C,D,E,...]
Not sure if there is a faster way, but I think this should be pretty fast (using the built-in unique function of numpy and choosing axis=0 to look for nxn unique arrays. More detail in thenumpy doc ):
[i for i in np.unique(np.array(List),axis=0)]
Example:
A = np.array([[1,1],[1,1]])
B = np.array([[1,1],[1,2]])
List = [A,B,A]
[array([[1, 1],
[1, 1]]),
array([[1, 1],
[1, 2]]),
array([[1, 1],
[1, 1]])]
Output:
[array([[1, 1],
[1, 1]]),
array([[1, 1],
[1, 2]])]
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