How to print python console error in my log file

Question

This is my code printing logs also. If you will replace (1,0,-4) with (1,0,1) at the bottom of page, you will get an valueerror. So, I want to print this error in my mathslog.txt file,how to do it? Code is starting from here:

import logging
import math


LOG_FORMAT = "%(levelname)s - %(asctime)s - %(message)s"
logging.basicConfig(filename="E:\\logs\\mathslogs.log", level= logging.DEBUG, filemode='w',format= LOG_FORMAT ,datefmt= '%y/%m/%d %I:%M:%S %p')


logger = logging.getLogger()


def quadraticc_formula(a,b,c):
    """Return the solutions to the equation ax^2 + bx + c=0."""
    
    logger.info("Calculating quadratic_formula for values ({0},{1},{2})".format(a,b,c))
    
    #Compute the discrminant
    logger.debug("#Compute the discriminant")
    disc = b**2 - 4*a*c
    
    # Compute the two roots
    logger.debug("Compute the two roots")
    root1 = (-b + math.sqrt(disc))/(2*a)
    root2 = (-b - math.sqrt(disc))/(2*a)
    
    #Return the roots
    logger.debug("#Successfully Calculated")

    
    
    return (root1,root2)
   

roots = quadraticc_formula(1,0,-4)
print(roots)

Answer 1

you can write this in log file also,by using exception to log.

try:
   roots = quadraticc_formula(1,0,-4) print(roots)
except Exception as msg:
   log.error(msg)     #writes in log file

Answer 2

Another method, if you want to catch all uncaught exceptions in your logger, is to take advantage of sys module's excepthook . Doing this once will make all exceptions go through your logger. This leaves freedom for you to use try except blocks that actually make more sense programmatically.

# set the excepthook to route through your logger before you call quadraticc_formula
sys.excepthook = lambda type, value, tb: logger.exception(value)

Here's a link to a more thorough discussion: Using python's logging module to log all exceptions and errors