#include <functional>
#include <iostream>
class Plain {
public:
template <typename Type>
void member_function(const Type& s) {
std::cout << "Recived: " << s << std::endl;
}
};
template <typename Type>
class Templated : private Plain {
public:
};
int main() {
Plain b;
b.member_function<int>(10); // done!
Templated<int> d;
// d.member_function(); /* how to achive this */
return 0;
}
I am trying to call the member function in class Plain
by two method:
Plain p;
p.member_function<int>();
Templated<int> t;
t.member_function(); // achive this
I tried doing binding the function in derived class like
struct Plain{
template<typename T>
static void member_function(const T& s){std::cout << s << std::endl;}
}
template<typename T>
struct Templated : private Plain {
std::function<void(const T&)> print = Templated::Plain::member_function;
}
and after that I was able to do
Templated t<std::string>;
t.print();
When you use private inheritance the methods in Plain are inaccessible to outside code, and you need to have something inside of Templated make the call to the method in Plain; you can do so, or alternatively you could use public inheritance and be able to hit it directly.
class Plain {
public:
template <typename T>
void print(const T & s) {
std::cout << "Received: " << s << std::endl;
}
};
template <typename T>
class Templated : private Plain {
public:
void print(const T & s) {
Plain::print<T>(s);
}
};
template <typename T>
class Alternative : public Plain {};
int main() {
Templated<int> t;
t.print(3); // This could work
Alternative<int> a;
a.print(4); // As could this
return 0;
}
I found a workaround
#include <functional>
#include <iostream>
using namespace std::placeholders;
struct Test {
template <typename Type>
void foo(const Type&) {
std::cout << "I am just a foo..." << std::endl;
return;
}
};
template <typename T>
struct Foo {
private:
Test* obj;
public:
Foo() : obj(new Test) {}
std::function<void(const int&)> foo = std::bind(&Test::foo<T>, obj, _1);
~Foo() { delete obj; }
};
int main() {
Foo<int> me;
me.foo(10);
Test t;
t.foo<int>(89);
std::cout << std::endl;
return 0;
}
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