How to avoid requests.exceptions.ConnectionError for printing url text?

Question

I cannot print the text of the url. What am I doing wrong?

import requests

r = requests.get('https://www.autozone.com/ecomm/b2c/v1/browse/page/getProductFitVehicles?skuId=937722&productLineCode=NGK&partNumber=4469')

print(r.text)

Traceback

requests.exceptions.ConnectionError: ('Connection aborted.', ConnectionResetError(54, 'Connection reset by peer'))

Answer 1

You need to set a user agent, it doesnt even have to be something coherent

import requests
#Set headers
headers = {'user-agent': 'my-app/0.0.1'}
#Add , headers=headers at the end of line before closing the parentheses
r = requests.get('https://www.autozone.com/ecomm/b2c/v1/browse/page/getProductFitVehicles?skuId=937722&productLineCode=NGK&partNumber=4469', headers=headers)

print(r.text)

Answer 2

r is not a variable but an object. Seems like you want to print the responce, try this:

print(r.content)

OR

print(r.text)