neo4j how to return all paths from a selected starting node

Question

Hello I have a graph db like this one:

my wish is to retrieve all the nodes connected through the r relationship starting from a selected node. Eg

if I select a , then I expect two rows as a response:

a,b,c
a,d

if I select b then I expect one row:

b,c

I tried with match p=(:a)-[:r*..]->() return p but it returns this

and in python I get this that i don't know how to parse:

<Path start=<Node id=93 labels=frozenset({'a'}) properties={'name': 'A'}> end=<Node id=94 labels=frozenset({'b'}) properties={'name': 'B'}> size=1>
<Path start=<Node id=93 labels=frozenset({'a'}) properties={'name': 'A'}> end=<Node id=95 labels=frozenset({'c'}) properties={'name': 'C'}> size=2>
<Path start=<Node id=93 labels=frozenset({'a'}) properties={'name': 'A'}> end=<Node id=96 labels=frozenset({'d'}) properties={'name': 'D'}> size=1>

Edit: I discovered function nodes() so I tried with match p=(:a)-[:r*..]->() return nodes(p) that returns kinda what I need:

but it still duplicates the path a,b,c in a,b and a,b,c . How can I remove the first row?

Answer 1

Regarding the question of duplicate path, one trick is to exclude paths whose end node is not a leaf, ie there are relationships starting from it. Eg:

MATCH p=(parent {name: "a"})-[:r*1..10]->(child)
WHERE NOT (child)-[:r]->()
RETURN p

For your second question about the return format, you can use a combination of UNWIND and collect like this:

MATCH p=(parent {name: "a"})-[:r*1..10]->(child)
WHERE NOT (child)-[:r]->()
UNWIND nodes(p) as node
WITH p, collect(node.name) as names
RETURN names

The result is:

╒═════════════╕
│"names"      │
╞═════════════╡
│["a","b","c"]│
├─────────────┤
│["a","d"]    │
└─────────────┘