class Count(models.Model):
start_time = models.DateTimeField(null = True, blank = True)
end_time = models.DateTimeField(null = True, blank = True)
class AccessRecord(models.Model):
user = models.ForeignKey(get_user_model(), related_name = 'accesses', on_delete = models.CASCADE)
count = models.ForeignKey(Count, related_name = 'accesses', on_delete = models.CASCADE)
With this model scheme, how can i filter on a Count queryset based on the user?
For example, i want every count object that has the first Access Record with a certain user id.
user_id = 2
all_counts = Count.objects.all()
list(filter(lambda x: x.accesses.first().user.pk == user_id, all_counts))
^^ This would work. However i get a list instead of a query set (i still need to order_by, etc..)
What's the best alternative here?
Edit. Every Count is guaranteed to have at least one Access Record.
You can also use accesses
as within a filter.
Thus Count.objects.filter(accesses__user_id=2)
But this will retrieve all Count's for this use, not just the ones for each first AccessRecord.
Thus by adding an order by you can do something like
first_acccess_count = Count.objects.filter(accesses__user_id=2).order_by('start_time').first()
Note: first_acccess_count
can be None, if user had no access yet.
Edit: Question was unclear, query should do: I want every count object of that user_id. But the user needs to have the first Access Record.
from django.db.models import Max
# First retrieve all first created AccessRecord's, by grouping on
# Count and to find all lowest ids of AccessRecords. As lower id
# can be seen as created first.
all_first_records_qs = AccessRecord.objects.values_list('count_id') \
.annotate(max_id=Min('id')).values_list('max_id', flat=True)
# values_list returns a QuerySet, and thus lazy, which allows it to
# be used as a subquery
all_counts = Count.objects.filter(
accesses__user_id=2,
accesses__id__in=all_first_records_qs,
)
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