Let's suppose I have the following list:
a = [0,5,10,11,15,22]
...and I want to make sure that the list elements are always a minimum of 5 apart from each other, how could I do that?
expected result:
[0,5,10,15,22]
What I tried is not very pythonic:
a.sort()
prev_elem = a[0]
new_list = []
for elem in a[1:]:
if abs(prev_elem-elem) >= 5:
new_list.append(prev_elem)
# update
prev_elem = elem
EDIT: BEFORE YOU DOWNVOTE : Why are you downvoting? Please add a comment? I am asking a question and I have shown my work, so there is no reason to downvote.
You can do it with a few very small changes to your existing code.
Lines that are changed are commented below.
a = [0,5,10,11,15,22]
a.sort()
prev_elem = a[0]
new_list = [prev_elem] # <====== initialise with one element
for elem in a[1:]:
if abs(prev_elem-elem) >= 5:
new_list.append(elem) # <===== append the new element
prev_elem = elem # <===== indented more (inside "if" block)
print(new_list)
This gives:
[0, 5, 10, 15, 22]
Iterate through the list. If arr[i]+5 >arr[i+1], then delete arr[i+1]. Something like the following code.
i = 0
while i < len(arr)-1:
if arr[i]+5 > arr[i+1]:
del arr[i+1]
else:
i+=1
There's definitely cleaner and more efficient ways to do this, but this should work.
Note this is pseudo code where n is the length of the array named arr:
for i = 1 to n
if (arr[i] - arr[i - 1] >= 5 OR arr[i] - arr[i - 1] <= -5)
//remove arr[i]
One way of doing it:
a = [0,5,10,11,15,22]
result = []
for i, num in enumerate(a):
if i == 0:
result.append(num)
continue
if 3 <= abs(num - a[i-1]):
result.append(num)
# [0,5,10,11,15,22] -> [0, 5, 10, 15, 22]
# [10, 9, 5, 0] -> [10, 5, 0]
# [10, 14, 9, 11, 5, 7, 0] -> [10, 14, 9, 5, 0]
EDIT:
I realized that it can be done simpler. Using slice and unpacking avoids index error in case of empty list:
result = [*a[0:1]]
for num in a[1:]:
if 3 <= abs(num - result[-1]):
result.append(num)
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