I have made a recursive way of printing all of the elements of a vector, but it returns nonsense! and it throws a really strange exception:
Exception thrown: read access violation.
std::vector<int,std::allocator<int> >::operator[](...) returned nullptr.
And it outputs: 12358000
This is the code. What is the mistake I have made?
#include <iostream>
#include <vector>
using namespace std;
int printVec(vector<int>* foo) {
if ((*foo).empty())
return 0;
else {
cout << (*foo)[0];
printVec(foo + 4);
}
}
int main() {
vector<int> ref{ 1,2,3,4,5,6,7,8,9,0 };
printVec(&ref);
}
foo
is a pointer to a std::vector<int>
.
foo + 4
is adding 4 lots of sizeof(std::vector<int>)
to foo
in pointer arithmetic. There is not a std::vector
at that location, so the behaviour of printVec(foo + 4)
is undefined.
The expression (*foo)[0]
is calling the overloaded []
operator on a std::vector
which access the first element in the vector. If there is no element at that position then the behaviour of the program is undefined.
What is the mistake I have made?
You are using a pointer to a single vector and treat it as if it points into an array of std::vector<int>
. It is only allowed to increment pointers that point to elements in arrays (actually you are allowed to get a pointer one past an object, but not more). A single std::vector
is not an array and your code invokes undefined behavior by incrementing foo
here: printVec(foo + 4);
.
If you want to "point to" elements of the vector use iterators:
#include <iostream>
#include <vector>
using namespace std;
template <typename IT>
void printVec(IT current, IT end) {
if (current == end) return;
else {
cout << *current;
printVec(current+1,end);
}
}
int main() {
vector<int> ref{ 1,2,3,4,5,6,7,8,9,0 };
printVec(ref.begin(),ref.end());
}
What is the structure of a std::vector?
You need not know nor care. If you want to iterate elements use iterators. If you want to access the underlying array use .data()
.
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