The runtime is NodeJS, I'm trying to replace the text $Contact
with a name. But I also need the ability to capture words around the term enclosed in curly brackets {}
:
Where Name = John:
My name is $Contact => My name is John
Hello {I am $Contact} => Hello I am John
Where Name = null:
My name is $Contact => My name is
Hello {I am $Contact} => Hello
The idea is to replace the $Contact
qualifier with a string, and OPTIONALLY the text enclosed in brackets is only displayed if the string is not empty. The use of curly brackets is optional.
// m = Message template (Hello {I am $Contact})
// qualifier = $Contact
// value = value to replace with
const replaceQualifier = (m, qualifier, value) =>
m.replace(new RegExp('\\{?(.*?)\\' + qualifier + '(.*?)\\}?', 'g'), value ? `$1${value}$2` : '');
It seems to work for qualifiers without curly brackets but not with curly brackets.
You need to use
m.replace(new RegExp('(?:\\{([^{}]*))?\\' + qualifier + '(?:([^{}]*)})?', 'g'),
value ? `$1${value}$2` : '');
The regex will look like
(?:\{([^{}]*))?\$Contact(?:([^{}]*)})?
See the regex demo . Details :
(?:\{([^{}]*))?
- an optional occurrence of {
and then (Group 1) any 0 or more chars other than {
and }
\$Contact
- $Contact
(?:([^{}]*)})?
- an optional occurrence of (Group 2) any 0 or more chars other than {
and }
and then }
. See the JS demo:
const replaceQualifier = (m, qualifier, value) => m.replace(new RegExp('(?:\\{([^{}]*))?\\' + qualifier + '(?:([^{}]*)})?', 'g'), value? `$1${value}$2`: ''); const qualifier = '$Contact'; let m = 'Hello {I am $Contact}'; let value = 'John'; console.log(replaceQualifier(m, qualifier, value)); value = ''; console.log(replaceQualifier(m, qualifier, value)); m = 'My name is $Contact'; value = 'John'; console.log(replaceQualifier(m, qualifier, value)); value = ''; console.log(replaceQualifier(m, qualifier, value));
Try this solution
var str1 = "My name is $Contact" var str2 = "My name is {$Contact}" var str3 = "Hello {I am $Contact}" const replaceQualifier = (m, qualifier, value) => m.replace(new RegExp(`(?:\\{(.*?))?\\${qualifier}(?:(.*?)\\})?`), value? `$1${value}$2`: ''); console.log(replaceQualifier(str1,"$Contact","John")) console.log(replaceQualifier(str2,"$Contact","John")) console.log(replaceQualifier(str3,"$Contact","John")) console.log(replaceQualifier(str1,"$Contact")) console.log(replaceQualifier(str2,"$Contact")) console.log(replaceQualifier(str3,"$Contact"))
Output:
My name is John
My name is John
Hello I am John
My name is
My name is
Hello
The solution is very similar to yours, just the groups are used differently:
(?...)
... non-capturing ("plain") parentheses \\{(.*?)
... {
followed by a captured group (.*?)
(?:\\{(.*?))?
... present zero or more times while debugging replace
, look first what is match
ed, for debugging purposes without the g
flag. In this case, \{?(.*?)
= optional {
character, then (grouped) zero or more of any character and then the qualifier
, ie the group is entire string before qualifier
(because the {
is optional )
In the proposed solution, the entire block \{(.*?)
is made optional, ie matching the {...
part of the string if present, but does not match anything otherwise.
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