XSLT transforming an XML with references
Question
I'm pretty new to xml & xslt and programming in general. I'm trying to transform an xml-file with xslt. My xml-file should reflect this ERD . In order to design the relationships between the entities I decided to use some id's. Here is my xml-code:
<?xml version="1.0" encoding= "UTF-8"?>
<data>
<aisles>
<aisle idaisle="A">
<letteraisle>A</letteraisle>
</aisle>
<aisle idaisle="B">
<letteraisle>B</letteraisle>
</aisle>
</aisles>
<shelves>
<shelf idshelf = "A1">
<numbershelf>1</numbershelf>
<lettershelf>A</lettershelf>
<aisleid idaisle="A"/>
</shelf>
<shelf idshelf = "A2">
<numbershelf>2</numbershelf>
<lettershelf>A</lettershelf>
<aisleid idaisle="A"/>
</shelf>
<shelf idshelf = "B1">
<numbershelf>1</numbershelf>
<lettershelf>B</lettershelf>
<aisleid idaisle="B"/>
</shelf>
<shelf idshelf = "B2">
<numbershelf>1</numbershelf>
<lettershelf>B</lettershelf>
<aisleid idaisle="B"/>
</shelf>
</shelves>
<boardgames>
<boardgame>
<name>Cuckoo in a Dark Forest (Kukacka v temném lese) </name>
<productnumber>1301976024</productnumber>
<price>94.7</price>
<shelfid idshelf="B1"/>
</boardgame>
<boardgame>
<name>The Underneath</name>
<productnumber>9117616387</productnumber>
<price>107.4</price>
<shelfid idshelf="A2"/>
</boardgame>
</boardgames>
</data>
And here is my xslt-code:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<html>
<head>
<link rel="stylesheet"
href="https://stackpath.bootstrapcdn.com/bootstrap/4.5.2/css/bootstrap.min.css" />
</head>
<body>
<table>
<tr>
<td>Name</td>
<td>Price</td>
<td>Product number</td>
<td>Shelf</td>
<td>Shelfnumber</td>
<td>Aisle</td>
</tr>
<xsl:for-each select="data/boardgames/boardgame">
<tr>
<td><xsl:value-of select="name"/></td>
<td><xsl:value-of select="price"/></td>
<td><xsl:value-of select="productnumber"/></td>
<td><xsl:value-of select="shelfid"/></td>
</tr>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
I wanted my xslt to transform all information contained in the boardgame-element. I thought if I would select "shelfid" in the boardgame-element then it would select the referenced element and its values as well. I tried to transform it. The price, name and productnumber worked as they were transformed correctly. But the values in the shelf-element didn't, which I tried to transform via the shelfid in the boardgame-element. Is it possible to select all values of a referenced sibling? If yes, how? I hope you understand what I mean. Thanks for your help!
1 answers
solution1
0 ACCPTED 2020-09-29 17:03:15
XSLT has a built-in key mechanism for resolving cross-references. Consider the following example:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:key name="aisle" match="aisle" use="@idaisle" />
<xsl:key name="shelf" match="shelf" use="@idshelf" />
<xsl:template match="/data">
<html>
<body>
<table border="1">
<tr>
<th>Name</th>
<th>Price</th>
<th>Product Number</th>
<th>Shelf Letter</th>
<th>Shelf Number</th>
<th>Aisle Letter</th>
</tr>
<xsl:for-each select="boardgames/boardgame">
<tr>
<td>
<xsl:value-of select="name"/>
</td>
<td>
<xsl:value-of select="price"/>
</td>
<td>
<xsl:value-of select="productnumber"/>
</td>
<xsl:variable name="shelf" select="key('shelf', shelfid/@idshelf)" />
<td>
<xsl:value-of select="$shelf/lettershelf"/>
</td>
<td>
<xsl:value-of select="$shelf/numbershelf"/>
</td>
<td>
<xsl:value-of select="key('aisle', $shelf/aisleid/@idaisle)/letteraisle"/>
</td>
</tr>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
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