n=3
*
* *
* *
* *
*
n=5
*
* *
* *
* *
* *
* *
* *
* *
*
I tried this but I don't use n=3 or n=5
for row in range(5):
for col in range(5):
if row+col==2 or col-row==2 or row-col==2 or row+col==6:
print("*",end="")
else:
print(end=" ")
print()
And when I run it
*
* *
* *
* *
*
I need to make diamond shape with loop, but I'm really new to python, can someone help me? Thanks in advance!
Here's the general form of this function, which takes n
and produces diamonds that match the two shown in the question, and all other sizes as well:
def diamond(n):
print("n=" + str(n))
nn = 2 * n - 1
for row in range(nn):
for col in range(nn):
if row+col==n-1 or col-row==n-1 or row-col==n-1 or row+col==3*(n-1):
print("*",end="")
else:
print(end=" ")
print()
diamond(3)
diamond(5)
diamond(7)
Result:
n=3
*
* *
* *
* *
*
n=5
*
* *
* *
* *
* *
* *
* *
* *
*
n=7
*
* *
* *
* *
* *
* *
* *
* *
* *
* *
* *
* *
*
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.