I have a numpy matrix of integers whose elements represent indices. I would like to create a matrix of the same size whose elements are taken from a list at the respective index.
import numpy as np
matrix = np.array([[0, 1, 1], [2, 0, 1]], dtype=int)
matrix
# array([[0, 1, 1],
# [2, 0, 1]])
values = [7, 8, 9]
values[matrix] # gives 'ValueError: can only convert an array of size 1 to a Python scalar'
Expected output:
# array([[7, 8, 8],
# [9, 7, 8]])
How can I do this in numpy?
Ok, I just found out I works as expected when values
is also an np.ndarray
instead of a list. So this works:
import numpy as np
matrix = np.array([[0, 1, 1], [2, 0, 1]], dtype=int)
matrix
# array([[0, 1, 1],
# [2, 0, 1]])
values = np.array([7, 8, 9])
values[matrix]
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.