I just wanna preface this by saying that I'm a beginner and I'm sorry if this is a stupid question/obvious mistake.
I'm making a human vs computer tic tac toe game, and the break statement is not breaking the innermost loop. The problem arises in the very last loop where even if the human wins, the if conditon below it is not executed. It goes on to play the computer's move and THEN declare that the computer has won.
please do inform me if I should change or add something to my question.
Thank You
boardkeys={9:' ',8:' ',7:' ',6:' ',5:' ',4:' ',3:' ',2:' ',1:' '}
def wincon():
if boardkeys[1]==boardkeys[2]==boardkeys[3]!=' ':
return True
elif boardkeys[4]==boardkeys[5]==boardkeys[6]!=' ':
return True
elif boardkeys[7]==boardkeys[8]==boardkeys[9]!=' ':
return True
elif boardkeys[1]==boardkeys[4]==boardkeys[7]!=' ':
return True
elif boardkeys[2]==boardkeys[5]==boardkeys[8]!=' ':
return True
elif boardkeys[3]==boardkeys[6]==boardkeys[9]!=' ':
return True
elif boardkeys[1]==boardkeys[5]==boardkeys[9]!=' ':
return True
elif boardkeys[3]==boardkeys[5]==boardkeys[7]!=' ':
return True
hsym=" O "
csym=" X "
def ai():
z=random.randrange(1,10)
while boardkeys[z]!=" ":
z=random.randrange(1,10)
boardkeys[z]=csym
def move():
no=int(input("enter your move human"))
if boardkeys[no]==" ":
boardkeys[no]=hsym
else:
print("invalid move")
move()
for i in range(10):
count=0
move()
count+=1
printboard()
if wincon==True: ????
print("Game Over you won") ????
break ????
elif count==9:
print("TIED")
break
else:
print()
print("computer's turn")
ai()
printboard()
if wincon()==True:
print("Game Over computer won")
break
elif count==9:
print("TIED")
break
Instead of if wincon==True:
it should be if wincon()==True:
, you're calling a function, not reading a boolean.
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