bash Execute command after another one finishes

Question

I have a list of files and my small program called app . My list is file01.txt to file1000.txt . I want to create a bash script that runs one by one:

app -i list01.txt     # to the file1000.txt

I want to execute the commands one by one, when the previous command finishes. Am I doing it in the right way in my example?

#!/bin/bash
app -i list01.txt;
app -i list02.txt;
app -i list03.txt;

Answer 1

You can use seq to generate all the commands:

seq -f 'echo app -i file%02.0f.txt' 1 1000 | sh

If the output looks right, remove the echo

Answer 2

If your app is running in standard foreground CLI (terminal) mode, you are right. This way, everything runs one by one, top to bottom.

Another way to run app2 only after app1 is as follows:

app1 && app2