Assign Extracted text from HTML table to Variable for later use -- Beautiful Soup / Python 3.7

Question

I have the below code working perfectly to dynamically search for a specific text within a HTML table source code and pull the nextSibling of the row where the specific text was found.

Current Code

r = requests.get(url)
soup = BeautifulSoup(r.text, 'lxml')
           
# Find xxxxxxx (row-by-row) and split trailing zeros
row = soup.find_all('td', string="xxxxxxx")
for r in row:
        LE = r.nextSibling
        while LE.name != 'td' and LE is not None:
                LE = LE.nextSibling

The main issue I am having (it is probably super easy and I have just been staring at this for so long now) is that I need to assign the nextSibling to the LE variable.

LE is formatted as "001234" where I need to strip the leading zeros to have "1234" as the variable.

If I print the variable as print(LE.text[2:6]) the result is correct. Implemented into the code as, LE = LE.nextSibling.text[2:6] does not produce anything.

I have tried the following statements, but none work and am hoping for guidance.

LE = LE.nextSibling.text[2:6]
&
LE = LE.text[2:6]

I need this to be assigned to a variable after extracting to utilize the variable later on within my script. I appreciate the help in advance!

EDIT --> included source code:

<tr>
     <td class='label' nowrap title="xxxxxxx">TEXT TO FIND</td>
     <td class='attribute'>001234</td>
</tr>

Answer 1

You can use next_sibling twice, and than use strip() to remove 0 :

from bs4 import BeautifulSoup

html = """<tr>
     <td class='label' nowrap title="xxxx">TEXT TO FIND</td>
     <td class='attribute'>001234</td>
</tr>"""

soup = BeautifulSoup(html, "html.parser")

for tag in soup.select(".label"):
    le = ''.join([t.strip("0") for t in tag.next_sibling.next_sibling])
    print(tag.text)
    print(le)

Output:

TEXT TO FIND
1234

Answer 2

Change:

!= to ==

 row = soup.find_all('td', string="xxxxxx")
            for r in row:
                LE = r.nextSibling
                    LE = LE.text[2:6]