awk print the field associated with specific last record

Question

I have a question about awk print.

here's my brief data file format

$cat file.dat

1 3 5 7 9
2 3 7 5 9
7 8 2 4 6
0 2 0 3 4

I want to print the column using "awk" If the last record value of the n-th column is greater than 0,

like this form

$cat file2.dat

3 7 9
3 5 9 
8 4 6
2 3 4

How can I do this?

Answer 1

awk -v col=3 '$NF > 0 { print $col }' file

Specify the column to print using the variable col. Then when the last column entry ($NF) is greater than 0, print the entry of the column specified by col ($col)