简体   繁体   中英

finding angles 0-360 in arctan

I need help with a math issue:

I need to get the angle from 0 until 360 degrees but this code gives the angle between -90 until 90 degrees:

N = math.cos(β * (math.pi / 180)) * math.tan((f + ω) * (math.pi / 180))
N2 = math.atan(N) * (180 / math.pi)

I want to N2 change between 0 to 360 degrees.

Use atan2 like so

import math
math.atan2(-0.1, 0.1) + math.pi

The problem is atan does not know which quadrant you are in, while atan2 does as it accepts an x and y coordinate as input.

If you compute atan(y / x) you need to switch things around so you compute atan2(y, x) instead. I can't understand how that relates to your example exactly.

The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM