Array=[3,4,5,6,7,6,7]. Temp=[1,2] how to store the value of temp in the array's 5th and 6th index in JavaScript

Question

Array=[3,4,5,6,7,6,7]
Temp=[1,2]

how to store the value of temp in the array's 5th and 6th index in JavaScript

Answer 1

Use the array.splice function arr.splice(index, 0, item); will insert item into arr at the specified index (deleting 0 items first, that is, it's just an insert).

This in combination with ...array to insert the values of the array instead of the array itself

 let Array=[3,4,5,6,7,6,7]; console.log(Array); let Temp=[1,2] Array.splice(5, 0, ...Temp); console.log(Array);

Refering this article

Answer 2

splice not only deletes items. You can also use it to insert items into the array. To effectively "spread" temp , you need the spread operator :

array.splice(5, 0, ...temp);

Then you can reuse splice to delete the old items:

array.splice(7, 2);

Answer 3

You could use splice , but it would mutate your original array

For safer use, make the result in the whole new array without affecting the original one, here I suggest using slice

 const array=[3,4,5,6,7,6,7] const temp=[1,2] const res = [array.slice(0, 5), temp, array.slice(5)].flat() console.log(res)

Answer 4

 const arr = [3,4,5,6,7,6,7]; const temp = [1, 2]; const res = [...arr.slice(0, 5), ...temp, ...arr.slice(5)]; console.log(res);

You can destructure the first part from your array until index 5 and the rest like this, you don't need to use .flat() to flatten the array.