Having problems with practicing loop in python

Question

import time
import random
import math

start = 1
stop = 10

for i in range(start, stop):
    time.sleep(1)
    print("\ni = {}".format(i), end = "")
    count = 3 + random.randint(1,5)
    print(", count = {}".format(count))
    nums = []
    while len(nums) < count:
        for j in range(count):
            time.sleep(0.3)
            try:
                num = random.randint(-10,100)
                log = round(math.log(num),1)
            except:
                time.sleep(2)
                print("\nagain")
                break
            nums.append(log)
            print("\rnums = {}".format(nums), end = "")

What I want to do is giving a random integer count for each iteration i , then using a while loop to append the log of num to nums until the length of nums equals to count . Here num is a random integer between -10 and 100, and if num is given as 0 or below, I want to start the loop again from the very beginning of for i in range(start, stop): , which is time.sleep(1) , so that I can designate new count and make new nums .

So I executed the code above, and it starts the loop again from the beginning of while len(nums) < count: .

For example, what I expected was something like

i = 1, count = 7
nums = [4.2, 4.4, 2.9, 4.4]
again
i = 1, count = 5
nums = [3.5, 3.6, 4.2]
again
i = 1, count = 6
nums = [2.0, 3.2, 3.5, 3.6, 4.2, 4.5]
i = 2, count = 5
nums = [4.5, 4.1, 4.0, 3.9, 3.8]
i = 3, count = 6
nums = [4.3, 3.8]
again
i = 3, count = 5
nums = [3.0, 3.4, 4.6, 3.6, 3.1]

and so on

And what I got is

i = 1, count = 7
nums = [4.2, 4.4, 2.9, 4.4, 3.2, 2.6]
again
nums = [4.2, 4.4, 2.9, 4.4, 3.2, 2.6, 4.0, 1.4, 3.5, 3.6, 3.5, 4.4, 2.9]
i = 2, count = 4

again
nums = [4.5, 4.1, 4.0, 3.9]
i = 3, count = 6
nums = [4.3, 3.8]
again
nums = [4.3, 3.8, 3.6, 2.3, 3.4, 4.6, 3.6, 3.1]
i = 4, count = 5
nums = [1.4, 3.0, 4.0, 4.4, 4.0]
i = 5, count = 7
nums = [4.4, 2.9, 3.5, 4.2, 3.6, 4.4, 4.6]

and so on

Answer 1

Put it all in a function and call it again whenever num is less than or equal to 0

import time
import random
import math

start = 1
stop = 10

def whatever():
    for i in range(start, stop):
        time.sleep(1)
        print("\ni = {}".format(i), end = "")
        count = 3 + random.randint(1,5)
        print(", count = {}".format(count))
        nums = []
        while len(nums) < count:
            for j in range(count):
                time.sleep(0.3)
                num = random.randint(-10,100)

                if num <= 0:
                    time.sleep(2)
                    print("\nagain")
                    whatever()
                else:
                    log = round(math.log(num),1)
                    nums.append(log)

                print("\rnums = {}".format(nums), end = "")

whatever()

This is where the loop will start again if num is less than or equal to 0

if num <= 0:
    time.sleep(2)
    print("\nagain")
    whatever()

Output :

i = 1, count = 8
nums = [4.2, 2.9, 3.8, 2.1, 4.0, 4.1, 3.8, 4.4]
i = 2, count = 5
nums = [3.4, 3.2, 3.6, 4.5]
again

i = 1, count = 8
nums = [3.5, 4.2, 4.3, 3.9, 3.5, 4.3, 1.1, 3.2]
i = 2, count = 7

again

i = 1, count = 8
nums = [2.4, 3.0, 4.5, 4.1, 4.2, 4.5, 3.6]