How can I sort a text file of winners' scores in order to print the top 5 winners?

Question

I am very new to coding. I am currently creating a dice game where players roll their die in 5 rounds, and the player who score the most points in total is the winner. I am able to write the Score and the player name in an external file, "Winners.txt" and it looks like:

25 - Hisham

20 - Jonothan

30 - Hi

28 - Lo

26 - Jonothan

32 - Hello

Is there anyway I can reorder the list so the score is descending? And how can I then print the top 5 winners? Thanks

Answer 1

You can do the following:

with open('Winners.txt') as f:
    l=f.readlines() #read the file and save lines to list
   
l=[i.split() for i in l] #split lines
l=[ i for i in l if i!=[]] #remove empty lines
l.sort(key=lambda x: int(x[0]), reverse=True) #sort lines by number descending

result=l[:5] #get the first 5

for i in result:
    print(i[0], i[-1]) #print first and last items of each line

Output:

32 Hello
30 Hi
28 Lo
26 Jonothan
25 Hisham

Answer 2

We'll need your code if you wish to make modifications in it only. Assuming that you just need to sort the names based on score, here's the code

file =open('winners.txt')
winner= file.read().split()
dictWin = {}

del winner[1::3]           #deletes '-' symbol

for i in range(0,len(winner),2):
    dictWin[winner[i]]=winner[i+1]

print(dictWin[max(dictWin.keys())])

You can use dictWin to get more specific data such as lowest score and rewrite sorted data in winners.txt