Calling up a def: function in an IF statement

Question

It's been a while since I used python (been studying CISCO IOS) so I'm bit rusty. I have forgotten how to assign a function to an IF statement.

import ipaddress

q1= input("Please enter 'network' to calculate an IP address range, or enter 'port' to scan an ip address for open ports  ")
if (q1 == str(network)):
    networkclac()
if (q1 == str(port)):
    portscan()


def networkclac():
    try:
        network = input('please input network address: ')
        network = ipaddress.ip_network(network)
        print(network)

    except ValueError:
        print('That is not a network address')

    iplist= list(ipaddress.ip_network(network).hosts())
    for i in range(10,len(iplist),2):
        print(iplist[i])

#def portscan():

Output

Traceback (most recent call last):
  File "C:\Users\shane\PycharmProjects\RodCertIV\ITCNWK409.py", line 4, in <module>
    if (q1 == str(network)):
NameError: name 'network' is not defined

Process finished with exit code 1

The aim of the program is to calculate a range of IP addresses, and scan ip addresses for open ports.

I have created the code for the IP Calculator, but I have forgotten how to call up a function in an IF statement.

I want the program, to ask the user if they wish to calculate an IP network address or run a port scan. If the end user inputs "network" I want the program to run the def network clac(): function

It's something quite simple that I'm missing, this should be an easy question for some.

EDIT I HAVE SLOVED THIS ISSUE WITH ASSISTANCE FROM THIS COMMUNITY, I POST UPDATED CODE BELOW

import ipaddress

def f1():
    try:
        network = input('please input network address with the prefix: ')
        network = ipaddress.ip_network(network)
        print(network)

    except ValueError:
        print('That is not a network address')

    iplist= list(ipaddress.ip_network(network).hosts())
    for i in range(10,len(iplist),2):
        print(iplist[i])

#def portscan():

print("Please enter 'network' to calculate an IP address range")
print("Please enter 'port' to scan for open ports")

q1= input("please input your choice:  ")
if q1 == "network":
    f1()
#if q1 == "port":
    #f2()

Now, I will work on the port scan function and ultimately convert this in to a GUI

Answer 1

Replacing str(network) with "network" and str(port) with "port" should work.

Answer 2

I was able to fix this problem by coding the user input section after the def function. Ie The computer reads the def function before it reads the user input function

import ipaddress

def f1():
    try:
        network = input('please input network address: ')
        network = ipaddress.ip_network(network)
        print(network)

    except ValueError:
        print('That is not a network address')

    iplist= list(ipaddress.ip_network(network).hosts())
    for i in range(10,len(iplist),2):
        print(iplist[i])

#def portscan():


q1= input("Please enter 'network' (with prefix) to calculate an IP address range, or enter 'port' to scan an ip address for open ports  ")
if q1 == "network":
    f1()
#if q1 == "port":
    #f2()