this is my code
list = [["UUU","UCU", "UAU", "UGU"],["UUC", " UCC ", "UAC", " UGC"]]
file = open("codons.txt","w")
for i in list:
for j in i:
file.write(j)
file.write(" ")
this is the desired output
UUU UCU UAU UGU
UUC UCC UAC UGC
You can do this:
The below code will concatenate all the values in each row, then add \n
to it and write to file.
my_list=[["UUU","UCU", "UAU", "UGU"],["UUC", " UCC ", "UAC", " UGC"]]
with open("codons.txt", "w") as f_out:
for line in my_list:
f_out.write(' '.join(line) + '\n')
Output of this will be:
UUU UCU UAU UGU
UUC UCC UAC UGC
Note here that I am not removing the leading and trailing spaces. If you want the leading and trailing spaces to be removed, the join() statement needs to be modified.
If you want the leading and trailing spaces to be stripped so the output looks like this:
UUU UCU UAU UGU
UUC UCC UAC UGC
Then use the below code instead:
my_list=[["UUU","UCU", "UAU", "UGU"],["UUC", " UCC ", "UAC", " UGC"]]
with open("codons.txt", "w") as f_out:
for line in my_list:
f_out.write(' '.join([item.strip() for item in line]) + '\n')
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.