How do I exclude a character in Linux

Question

Write a wildcard to match all files (does not matter the files are in which directory, just ask for the wildcard) named in the following rule: starts with a string “image”, immediately followed by a one-digit number (in the range of 0-9), then a non-digit char plus anything else, and ends with either “.jpg” or “.png”. For example, image7.jpg and image0abc.png should be matched by your wildcard while image2.txt or image11.png should not.

My folder contained these files imag2gh.jpeg image11.png image1agb.jpg image1.png image2gh.jpg image2.txt image5.png image70.jpg image7bn.jpg Screenshot.png

If my command work it should only display image1agb.jpg image1.png image2gh.jpg image5.png image70.jpg image7bn.jpg

This is the command I used (ls -ad image[0-9][^0-9]*{.jpg,.png}) but I'm only getting this image1agb.jpg image2gh.jpg image7bn.jpg so I'm missing (image1.png image5.png) Kali Terminal and what I did

ls -ad image[0-9][.0-9]*{,jpg..png}

Answer 1

Info

Character ranges like [0-9] are usually seen in RegEx statements and such. They won't work as shell globs (wildcards) like that.

Possible solution

1. Pipe output of command ls -a1 to standard input of the grep command (which does support RegEx).
2. Use a RegEx statement to make grep filter filenames.

ls -a1|grep "image"'[[:digit:]]\+[[:alpha:]]*\.\(png\|jpg\)'