sqlite3_stmt *stmt;
sqlite3_prepare_v2(db, "INSERT INTO links(NAME, LINK, SIZE, STARRED) VALUES ('?' , '?', ? , 0);", 41, &stmt, NULL);
if(stmt != NULL) {
sqlite3_bind_text(stmt, 1, name, 0, SQLITE_TRANSIENT);
sqlite3_bind_text(stmt, 2, link, 0, SQLITE_TRANSIENT);
sqlite3_bind_int(stmt, 3, size);
sqlite3_step(stmt);
sqlite3_finalize(stmt);
}else{
printf("%sError during insertion in the database%s\n", RED, RST);
}
sqlite3_close(db);
I always get on the output Error during insertion in the database
but can't understand why, maybe something related to sqlite3_prepare_v2
but doesn't know what, I tried to execute the query 'manually' with random data and it works.
You bind twice item 2 of the statement and? is missing for item 3.
The size of the zSql statement is 69 characters. It is is better to us -1 for length as by default it will be null-terminated string and size is automatically computed:
sqlite3_prepare_v2(db, "INSERT INTO links(NAME, LINK, SIZE, STARRED) VALUES (?, ?, ? , 0);", -1, &stmt, NULL);
Do not forget the 3rd '?' in the statement for the 3rd argument. Edit: write it as? in the statement
Just solved by changing the third parameter of sqlite3_prepare_v2()
that is the maximum length of zSql in bytes, and 47 is to small.
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