Consider following code:
public class A
{
public A(){}
}
public class B:A
{
public B(){}
}
public class C
{
public C(){}
public void fun(A a)
{
Console.WriteLine("that was A");
}
public void fun(B b)
{
Console.WriteLine("that was B");
}
}
public class Program
{
public static void Main()
{
A a = new A(), b = new B();
C c = new C();
c.fun(a);
c.fun(b);
}
}
In the current form, it says "that was A"
twice. How to fix class C
, so that fun(B b)
is invoked when b
's runtime type is B
, but compilation type is A
? Currently it works properly only when I declare b
as B
during compilation.
@Edit: without checking types with if
s etc.
Invoke fun
via a virtual method.
public class A
{
public virtual void fun(C c)
{
c.fun(this);
}
}
public class B:A
{
public override void fun(C c)
{
c.fun(this);
}
}
public class C
{
public void fun(A a)
{
Console.WriteLine("that was A");
}
public void fun(B b)
{
Console.WriteLine("that was B");
}
}
public class Program
{
public static void Main()
{
A a = new A(), b = new B();
C c = new C();
a.fun(c);
b.fun(c);
}
}
Output:
that was A
that was B
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