i see this document => https://github.com/doxtitech/url_launcher_package_example/blob/master/lib/main.dart
but I don't want to open the 'mailto'.
If the app package name is 'kr.go.eduro.hcs', how can I open that app when I press the button?
My CODE:
class _CoronaSubScreenState extends State<CoronaSubScreen> {
void customLaunch(command) async {
if (await canLaunch(command)) {
await launch(command);
} else {
print('$command is not load');
}
}
@override
Widget build(BuildContext context) {
return Scaffold(
appBar: AppBar(
title: Text(widget.title),
),
body: Center(
child: Column(
mainAxisAlignment: MainAxisAlignment.center,
children: <Widget>[
RaisedButton(
onPressed: () {
customLaunch('kr.go.eduro.hcs');
},
child: Text(
'self',
),
),
],
),
),
);
}
}
If you know application package name, you can do by using ' device_apps ' package.
// Check whether app is installed
bool isInstalled = await DeviceApps.isAppInstalled('com.frandroid.app');
// Call open the application what you want
DeviceApps.openApp('com.frandroid.app');
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