Is there any way to make an abstract class or interface for ViewBinding. Maybe I will show a simple example of what I exactly mean.
Let's say that I have two fragments. Both have TextView
named universalTextView
. In fragment classes I have value someText = "Text"
. I want to set this value to universalTextView
. Now in both fragments, I have the same code so I made an abstract class, to reduce boilerplate code, that holds someText
and set text for universalTextView
. It looks like this:
abstract class AbstractFragment(
@LayoutRes layout: Int
) : Fragment(layout)
{
protected abstract val binding: ViewBinding
protected val someText = "Text"
override fun onViewCreated(view: View, savedInstanceState: Bundle?)
{
super.onViewCreated(view, savedInstanceState)
binding.root.findViewById<TextView>(R.id.universalTextView).text = someText
}
}
But with this approach, I am losing the biggest advantage of ViewBinding and I have to use findViewById
. Is there any way to make an abstract class for ViewBinding, something like this:
abstract class AbstractViewBinding : ViewBinding
{
abstract val universalTextView : TextView
}
So in AbstractFragment
I can use protected abstract val binding: AbstractViewBinding
and change text without using findViewById
. But now, somehow I have to tell the app that ViewBinding used in every fragment that extends AbstractFragment
will have universalTextView
. Is this even possible?
I don't think this is directly possible, there isn't any sort of inheritance mechanism in view binding. Instead you could have a structure like this:
abstract class AbstractFragment : Fragment {
abstract val universalTextView: TextView
protected val someText = "Text"
override fun onViewCreated(view: View, savedInstanceState: Bundle?) {
super.onViewCreated(view, savedInstanceState)
universalTextView.text = someText
}
}
class Fragment1 : AbstractFragment {
lateinit var binding: Fragment1Binding
override val universalTextView
get() = binding.utv
}
but I realise this isn't quite what you wanted.
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