How to compare two fields in joi?

Question

I try to do validation between two fields. foo and bar .

1. Both should be a string but they optional. if they have some value it should be min of 2 and max of 10.
2. If both are empty (""/null/undefined) the validation should be failed and return error.

I try to do it with

.when("bar", { is: (v) => !!v, then: Joi.string().required() }),

But doesn't work the error return undefined .

Any idea how to solve that?

codesandbox.io

const Joi = require("joi");

console.clear();

const schema = Joi.object({
  foo: Joi.string()
    .allow("", null)
    .optional()
    .min(2)
    .max(10)
    .when("bar", {
      is: (v) => !!v,
      then: Joi.string().required()
    }),
  bar: Joi.string().allow("", null).optional().min(2).max(10)
});

const { error } = schema.validate(
  { foo: null, bar: null },
  { allowUnknown: true, abortEarly: false }
);

const { error: error2 } = schema.validate(
  { foo: null, bar: "text" },
  { allowUnknown: true, abortEarly: false }
);

console.log({ error }); // should be with error.
console.log({ error2 }); // should be undefiend.

if (error) {
  const { details } = error;
  console.log({ details });
}

if (error2) {
  const { details } = error2;
  console.log({ details });
}

Answer 1

This how you need to configure to achieve that

1. empty(['', null]) , considers '' and null as undefined .
2. or("foo", "bar") , makes one of them is required.

 const schema = Joi.object({ foo: Joi.string().empty(['', null]).min(2).max(10), bar: Joi.string().empty(['', null]).min(2).max(10) }).or("foo", "bar");

Answer 2

This is how it's done with Joi :

const schema = Joi.object({
    password: Joi.string()
        .pattern(new RegExp('^[a-zA-Z0-9]{3,30}$')),
    
    repeat_password: Joi.ref('password')
})
.with('password', 'repeat_password')

const { error } = schema.validate({ password: 'BlaBlaaa', repeat_password: 'Bla' })