An unexisting variable in print() in Python.PY code

Question

So, I tried to create a discord bot and I wrote this code:

import os

import discord
from dotenv import load_dotenv

load_dotenv()
TOKEN = os.getenv('DISCORD_TOKEN')
GUILD = os.getenv('DISCORD_GUILD')

client = discord.Client()


@client.event
async def on_ready():
    for guild in client.guilds:
        if guild.name == GUILD:
            break

    print(
        f'{client.user} is connected to the following guild:\n'
        f'{guild.name}(id: {guild.id})'
    )

client.run(TOKEN)

Then VSCode shown me this:

    f'{client.user} is connected to the following guild:\n'
UnboundLocalError: local variable 'guild' referenced before assignment

Idk where it found "guild" variable, please help me removing this error!

Answer 1

The problem is most likely that, guild may not be defined. For example:

This works:

for my_var in [0, 1]:
    pass

print(my_var)

This gives a NameError, because my_var is never defined.

for my_var in []:
    pass

print(my_var)

You need to set a default value for guild (you can do this by putting guild=None above your for-loop) or by putting the print statement inside the for-loop.

Answer 2

It was little big for comment.

I have changed your code a litte. As eror is unknown. This code will at least help you to identify error import os

import discord
import os
from dotenv import load_dotenv

load_dotenv()
TOKEN = os.getenv('DISCORD_TOKEN')
GUILD = os.getenv('DISCORD_GUILD')

client = discord.Client()


@client.event
async def on_ready():
    print(client.guilds) # try to print number of child of client.guilds. I think they are Zero
    for guild in client.guilds:
        if guild.name == GUILD:
            break # This break does not gurantee guild is initalized
    # safety check to make code showing proper error
    if guild is not None:
        print(dir(guild))
        print(
            f'{client.user} is connected to the following guild:\n'
            f'{guild.name}(id: {guild.id})'
        )

client.run(TOKEN)