elif not working on dictionary key-value pairs

Question

I am writing a function to clean data of dictionary which contains a key-value pairs showing a date and the rainfall on that date. The conditions for the cleaning of data requires the removal of and key-value pairs where the values meet the following conditions:

• the type is not an integer or a float. Even if the value is a string that could be converted to an integer (eg "5") it should be deleted.
• the value is less than 0: it's impossible to have a negative rainfall number, so this must be bad data.
• the value is greater than 100: the world record for rainfall in a day was 71.8 inches

def clean_data (adic):
    newDic = {}
    for (date,inches) in adic.items():  
        print (date,inches)
        if not type(inches) == float:
            if not type(inches) == int:
                print ("type")
                continue
        elif inches < 0:
            print ("below 0")
            continue
        elif inches > 100:
            print ("above 100")
            continue
        else:
            print ("added")
            newDic[date]=inches
    return newDic



rainfall = {"20190101": 5, "20190102": "6", "20190103": 7.5, 
           "20190104": 0, "20190105": -7, "20190106": 102,
           "20190107": 1}
print(clean_data(rainfall))

For some reason my code is outputting:

20190101 5
20190102 6
type
20190103 7.5
added
20190104 0
20190105 -7
20190106 102
20190107 1
{'20190103': 7.5}

So many of the key-value pairs are not behaving with the elif statements as I would expect. I can't figure out for example why the first key-value pair of 20190101 5 passes through all the if/elif statements put is not added to the new dictionary or why the 20190105 -7 key-value pair passes through the elif statement with value less than 0. When I change all these statements to if statements not elif statements the code works but as fair I can tell the statements are mutually exclusive so the elifs should work. I want the code to only run the one if or elif statement that is true, I don't need it to run all of them if one condition is met. I don't understand elifs are not working?

Answer 1

The 5 of 20190101 5 is not float, so it goes into the first branch

    if not type(inches) == float:

Since it entered here, it will not enter any elif s.

The 5 of 20190101 5 is integer, so this part does not execute:

        if not type(inches) == int:
            print ("type")
            continue

If your requirement is

the type is not an integer or a float.

(should actually be: the type is neither integer nor float )

Use if not type(inches) == float and not type(inches) == int:

Answer 2

rainfall = {"20190101": 5, "20190102": "6", "20190103": 7.5, 
           "20190104": 0, "20190105": -7, "20190106": 102,
           "20190107": 1}

5, 0, -7, 102, 1 are type of int . First if statement of if not type(inches) == float will handle it, and because they are int, they won't go to if statement if not type(inches) == int: .

"6" is string, neither float nor int. So it will print type message.

Only element that will be handled correctly is 7.5 .