How can I add chr() to a regex pattern in python?

Question

I want to replace the '-' in the regex pattern with chr(45) and '–' with chr(8211) .

I am trying to use the below code. Can you please help?

text = 'part number-–'

regex_str2 = r'(?i)(?<!\S)(part number|partno|part.no|part no|pn. nov|p\.no|pno|p/no|p/n|p / n|part|mpn|pn|pt)(\s)*[-–\.\*#:=\s]{1,}'
       
sub_ret = re.subn(regex_str2, 'PartNoId ', text)
print(sub_ret)

Answer 1

I want to replace the '-' in the regex pattern with chr(45) and '–' with chr(8211) .

I am trying to use the below code. Can you please help?

text = 'part number-–'

regex_str2 = r'(?i)(?<!\S)(part number|partno|part.no|part no|pn. nov|p\.no|pno|p/no|p/n|p / n|part|mpn|pn|pt)(\s)*[-–\.\*#:=\s]{1,}'
       
sub_ret = re.subn(regex_str2, 'PartNoId ', text)
print(sub_ret)

Answer 2

I want to replace the '-' in the regex pattern with chr(45) and '–' with chr(8211) .

I am trying to use the below code. Can you please help?

text = 'part number-–'

regex_str2 = r'(?i)(?<!\S)(part number|partno|part.no|part no|pn. nov|p\.no|pno|p/no|p/n|p / n|part|mpn|pn|pt)(\s)*[-–\.\*#:=\s]{1,}'
       
sub_ret = re.subn(regex_str2, 'PartNoId ', text)
print(sub_ret)