Make xsd.exe utility generate schema with strong types

Question

I have this sample XML file:

<?xml version="1.0"?>
<DocumentElement>
  <item>
    <id>1</id>
    <name>BBB</name>
  </item>
  <item>
    <id>2</id>
    <name>BBB</name>
  </item>
</DocumentElement>

I want to generate XSD schema using xsd.exe utility and run this command:

xsd.exe myXmlFile.xml

This is what I got on output:

<?xml version="1.0" encoding="utf-8"?>
<xs:schema id="DocumentElement" xmlns="" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:msdata="urn:schemas-microsoft-com:xml-msdata">
  <xs:element name="DocumentElement" msdata:IsDataSet="true" msdata:Locale="en-US">
    <xs:complexType>
      <xs:choice minOccurs="0" maxOccurs="unbounded">
        <xs:element name="item">
          <xs:complexType>
            <xs:sequence>
              <xs:element name="id" type="xs:string" minOccurs="0" />
              <xs:element name="name" type="xs:string" minOccurs="0" />
            </xs:sequence>
          </xs:complexType>
        </xs:element>
      </xs:choice>
    </xs:complexType>
  </xs:element>
</xs:schema>

Notice both fields are string but I expected them to be an integer and a string.
If I generate schema in VS then I get a better result:

      <xs:element name="id" type="xs:unsignedByte" />
      <xs:element name="name" type="xs:string" />

How can I make xsd.exe work like in VS?

Answer 1

You can try the following steps to generate xsd files with strong types.

First, please generate a xsd file by using the command:

xsd D:\Sample.xml /outputdir:D:\

Second , please generate a class from the xsd file:

xsd D:\Sample.xsd /classes /outputdir:D:\

Third , please create a class library(.net framework 3.5) and add the generated class to the project, rebuild it.

Fourth , please change string type to int type about id.

public partial class DocumentElementItem {

private int idField;        //Change string to int

private string nameField;

/// <remarks/>
[System.Xml.Serialization.XmlElementAttribute(Form=System.Xml.Schema.XmlSchemaForm.Unqualified)]
public int  id {          //Change string to int
    get {
        return this.idField;
    }
    set {
        this.idField = value;
    }
}

/// <remarks/>
[System.Xml.Serialization.XmlElementAttribute(Form=System.Xml.Schema.XmlSchemaForm.Unqualified)]
public string name {
    get {
        return this.nameField;
    }
    set {
        this.nameField = value;
    }
}

}

Finally , please use the following command to generate a xsd file with strong types.

xsd "D:\Test\bin\Debug\Test.dll" /type:DocumentElementItem /outputdir:D:\

You will get the following xsd file.

Besides, you can see all the processes in the following picture.