I have a dataset that has several rows and columns, however within the column labeled, 'number', I wish to remove the aggregation and separate this into its own unique count. I also wish to add a column that gives this count a unique id.
Data
location name type number year
ny hello he 1 2021
ny bye by 0 2021
ny ok o 2 2021
ca hi h 1 2021
Desired
location name type number year count
ny hello he 1 2021 he1
ny bye by 0 2021 by1
ny ok o 1 2021 o1
ny ok o 1 2021 o2
ca hi h 1 2021 h1
The string 'ok' is now separated into distinct rows, versus being aggregated with a value of 2. The values in the 'number' column are now separated into 2 distinct rows, along with a distinct count ID (based on the 'name' column) instead of an aggregation.
Doing
df = df1.reindex(df1.index.repeat(df1['number'])).assign(number=1)
df['count'] = df['type'] + '0' + (df.groupby(['location', 'name', 'type', 'number', 'year']).cumcount() + 1).astype(str)
df
I was helped by a SO member, however, in this example, how would I account for if values in the number column is 0? I am still researching this.
Any suggestion or advice is appreciated
Idea is split values for repeat only of number
is greater like 1
, then add rows with number=0,1
and sorting for original ordering:
m = df1['number'].gt(1)
df2 = df1[m]
df = (pd.concat([df2.reindex(df2.index.repeat(df2['number'])).assign(number=1),
df1[~m]]).sort_index())
df['count'] = df['type'] + '0' + (df.groupby(['location', 'name', 'type', 'number', 'year']).cumcount() + 1).astype(str)
print (df)
location name type number year count
0 ny hello he 1 2021 he01
1 ny bye by 0 2021 by01
2 ny ok o 1 2021 o01
2 ny ok o 1 2021 o02
3 ca hi h 1 2021 h01
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