If I had this list:
y =[a,b,c,d,e,f]
And I want to select a
and b
, then e
and f
, what's the syntax for that?
I've tried:
y = [a,b,c,d,e,f,g,h,i,j]
for letter in range(0,len(y),2):
print(letter)
The result I want is
[a, b, e, f i,j]
But instead I get every second letter:
a
c
e
g
i
When I've tried using slice notation print(y[:1]) I only get the first two values in the list.
You need to set the step to 4. For every 4 items, you need the first two(3 and 4 are skipped). so:
lst = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j']
new_list = []
for i in range(0, len(lst), 4):
new_list.append(lst[i])
new_list.append(lst[i + 1])
print(new_list)
If the iterable is really just a string/collection of characters:
from textwrap import wrap
from itertools import chain
print(list(chain.from_iterable(wrap("abcdefghij", 2)[::2])))
Output:
['a', 'b', 'e', 'f', 'i', 'j']
>>>
If it's an arbitrary iterable:
from itertools import islice, chain
def chunk_wise(iterable, chunk_size):
it = iter(iterable)
while chunk := list(islice(it, chunk_size)):
yield chunk
print(list(chain.from_iterable(islice(chunk_wise("abcdefghij", 2), 0, None, 2))))
Output:
['a', 'b', 'e', 'f', 'i', 'j']
>>>
The most straightforward way is to use a list comprehension with an if-clause ('filter') that will pick the items in your span that you want.
ls = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j']
ls_spans = [x for i, x in enumerate(ls) if i % 4 in [0,1]]
To tease this out more, what we do is a list comprehension:
ls_spans = [x for x in ls] # Essentially just copies the list
But we want to select only certain members of a 'span', which we identify as a 4-unit length: ( abcd
, efgh
, ij
in our list).
ls_spans = [x for x in ls if x_is_wanted()]
To do this, since the fact of whether we want x
or not is dependent on it's position, we use enumerate
to pair each element in the list with an index (the i
in the list comprehension below):
ls_spans = [x for i, x in enumerate(ls) if x_is_wanted(i)]
Now, we consider the function x_is_wanted
which has to say 'yes' or 'no' ( True
or False
) for each element:
def x_is_wanted(i: int) -> bool:
span_length = 4
acceptable_positions = [0, 1] # Remember we are 0-indexed!
return i % span_length in acceptable_positions # We use modulo to get the remainder, which is equivalent to the position in the span.
The complete program would probably look like:
def x_is_wanted(i: int) -> bool:
span_length = 4
acceptable_positions = [0, 1] # Remember we are 0-indexed!
return i % span_length in acceptable_positions
ls_spans = [x for i, x in enumerate(ls) if x_is_wanted(i)]
But we can more easily inline this, if we don't need to re-use the function:
# Play with these params to see what changes!
span_length = 4
acceptable_positions = [0, 1]
ls = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j']
ls_spans = [x for i, x in enumerate(ls) if i % span_length in acceptable_positions]
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