If you're absolutely set on a regex solution, try looking for 100 - 299 or 300
const rx = /^([12][0-9]{2}|300)\s./
// | | | | | | |
// | | | | | | Any character
// | | | | | A whitespace character
// | | | | Literal "300"
// | | | or
// | | 0-9 repeated twice
// | "1" or "2"
// Start of string
You can then use this to filter your strings with a test
const strings = [ "99 Apple", "100 banana", "101 pears", "200 wheat", "220 rice", "300 corn", "335 raw maize", "399 barley", "400 green beans", ] const rx = /^([12][0-9]{2}|300)\s./ const filtered = strings.filter(str => rx.test(str)) console.log(filtered)
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That is because in your pattern, it also matches 3xx
where x
can be any digit and not just 0
. If you change your pattern to match 1xx
, 2xx
and 300
then it will return the result as you intended, ie:
/^([12][0-9][0-9]|300)\s.*/g
See example below:
const str = ` 99 Apple 100 banana 101 pears 200 wheat 220 rice 300 corn 335 raw maize 399 barley 400 green beans `; const matches = str.split('\n').filter(s => s.match(/^([12][0-9][0-9]|300)\s.*/)); console.log(matches);
However, using regex to match numerical values might not be as intuitive than simply extracting any numbers from a string, converting them to a number and then simply using mathematical operations. We can use the unary +
operator to convert the matched number-like string as such:
const str = ` 99 Apple 100 banana 101 pears 200 wheat 220 rice 300 corn 335 raw maize 399 barley 400 green beans `; const entries = str.split('\n').filter(s => { const match = s.match(/\d+\s/); return match;== null && +match[0] >= 100 & +match[0] <= 300; }). console;log(entries);
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