I need to know which English words were used in the Italian chat and to count how many times they were used.
But in the output I also have the words I didn't use in the example chat (baby-blue-eyes': 0)
english_words = {}
with open("dizionarioen.txt") as f:
for line in f:
for word in line.strip().split():
english_words[word] = 0
with open("_chat.txt") as f:
for line in f:
for word in line.strip().split():
if word in english_words:
english_words[word] += 1
print(english_words)
You can simply iterate over your result and remove all elements that have value 0:
english_words = {}
with open("dizionarioen.txt") as f:
for line in f:
for word in line.strip().split():
english_words[word] = 0
with open("_chat.txt") as f:
for line in f:
for word in line.strip().split():
if word in english_words:
english_words[word] += 1
result = {key: value for key, value in english_words.items() if value}
print(result)
Also here is another solution that allows you to count words with usage of Counter:
from collections import Counter
with open("dizionarioen.txt") as f:
all_words = set(word for line in f for word in line.split())
with open("_chat.txt") as f:
result = Counter([word for line in f for word in line.split() if word in all_words])
print(result)
If you want to remove the words without occurrence after indexing, just delete these entries:
for w in list(english_words.keys()):
if english_words[w]==0: del english_words[w]
Then, your dictionary only contains words that occurred. Was that the question?
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