Sequelize Mock doesn't work properly with Sequelize function "count"

Question

When I use Sequelize Mock between with a query like that:

 const { active, 'in-progress': inProgress, } = await ImmediateCare.findAll({ raw: true, attributes: ['status', [fn('count', col('id')), 'count']], group: ['ImmediateCare.status'], }).then((status) => { const counts = { active: 0, 'in-progress': 0, } status.forEach((s) => { counts[s.status] = parseInt(s.count, 10) }) return counts })

Is being returned NaN , I'm guessing that is because Sequelize Mock can't mock sequelize.fn('count')

Is that right?

Answer 1

You can use Sinon along with Sequelize Mock and stub the findAll call with mock data. Something like this:

const sinon = require('sinon');
const SequelizeMock = require('sequelize-mock');
describe('', () => {
beforeEach(() => {
const dbConnection = new SequelizeMock();
const dbStub = sinon.stub(dbConnection, 'define');
const queryStub = sinon.stub().resolves(mockImmediateCareData);
dbStub.returns({ findAll : queryStub })
})
})

If this does not help, can you please share the defined mock object? Also, the . then() is not needed as await is already being used.

Answer 2

I was taking the wrong path

This is the test for the method.

I'm not supposed to test the Sequelize count response, I just need to mock the result