I have two tables, "keywords" and "stats" and want to know per keyword how many results each merchant has. So one row per keyword.
Desired result eg:
KWD | RESULTS Amazon | RESULTS eBay
test 3 5
second 6 2
The tables:
create table keywords
(
ID mediumint unsigned auto_increment
primary key,
KEYWORD varchar(255) null
);
create table stats
(
MERCHANT_ID tinyint unsigned not null,
TYPE_ID mediumint unsigned not null comment 'the ID of the coresponding type. E.g. kw_id from keywords',
RESULTS smallint unsigned null,
DATE date not null,
primary key (DATE, MERCHANT_ID, TYPE_ID)
)
comment 'How many results does each merchant have per search?';
Sample data:
-- keywords
insert into test.keywords (ID, KEYWORD) values (1, 'testing');
insert into test.keywords (ID, KEYWORD) values (2, 'blablub');
-- stats
insert into test.stats (MERCHANT_ID, TYPE_ID, RESULTS, DATE) values (1, 1, 33, '2021-07-06');
insert into test.stats (MERCHANT_ID, TYPE_ID, RESULTS, DATE) values (1, 2, 3, '2021-07-06');
insert into test.stats (MERCHANT_ID, TYPE_ID, RESULTS, DATE) values (2, 1, 22, '2021-07-06');
insert into test.stats (MERCHANT_ID, TYPE_ID, RESULTS, DATE) values (2, 2, 6, '2021-07-06');
The query:
select
kwd.KEYWORD,
mss.MERCHANT_ID,
mss.RESULTS
from keywords kwd
LEFT JOIN stats mss ON mss.TYPE_ID = kwd.ID
where
date = 20210705
group by kwd.ID
There are about 10 merchants. Is it possible to get one row per keyword and have the number of results per merchant in seperate colunns?
Try something like this:
select
kwd.KEYWORD,
SUM(IF(mss.MERCHANT_ID = 'amazon', mss.RESULTS, 0)) as `amazon_sum`,
SUM(IF(mss.MERCHANT_ID = 'eBay', mss.RESULTS, 0)) as `eBay_sum`
from keywords kwd
LEFT JOIN stats mss ON mss.TYPE_ID = kwd.ID
where
date = 20210705
group by kwd.ID
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