How can I make the if function in python try the values from the range for “a” and return the correct answer

Question

a = list(range(0,10))

if a + 6 == 10:
    print(a)

I am trying to make the numbers between 0 and 10 be individually substituted into a and when it finds the right answer then it will stop and return the value of a . So, in this case, just to return 4 .

I keep getting this error

can only concatenate list (not "int") to list

Answer 1

Here you go:

def func():
    for a in range(10):
        if a + 6 == 10:
            return a

Answer 2

You should iterate over the list a and then check your condition for each element of a

a = list(range(0,10))

for i in a:
    if i + 6 == 10:
        print(i)