Rerun PHP Script inside HTML file without reloading page

Question

I want to rerun a PHP File which was loaded in a div in my HTML code. On my main page, I have a form and a table. The form adds rows to the MySQL table, and the table on the page outputs that MySQL table. I want the table on the HTML page to update when the new row is added via the form, without refreshing the page. I tried putting the load command in the success part of the ajax function for my form but that didn't work. I looked at many other answers and none worked for me.

This is my code

redeem.php

        <h1>Rewards</h1>
        <form id="add-reward-form" action="" method="POST">
                <label for="inputRewardDescription" class="form-label">Enter Reward Description</label>
                <input type="text" id=inputRewardDescription name="description" class="form-control" required>
                
                <label for="inputRewardCost" class="form-label">Enter Reward Cost</label>
                <input type="text" id=inputRewardCost name="points" class="form-control" required>
    
                <button type="submit" class="btn btn-success" id="submit-btn">Save</button>
        </form>  
        <p id="message"></p>
        <div id="sql-table">
            <?php include 'tables.php'; ?>
        </div>

tables.php

<?php
        $host    = "";
        $user    = "";
        $pass    = "";
        $db_name = "";

        //create connection
        $connection = mysqli_connect($host, $user, $pass, $db_name);

        //test if connection failed
        if(mysqli_connect_errno()){
            die("connection failed: "
                . mysqli_connect_error()
                . " (" . mysqli_connect_errno()
                . ")");
        }

        //get results from database
        $result = mysqli_query($connection,"SELECT RewardName, PointsRequired FROM rewards");
        $all_reward = array();  //declare an array for saving property
            while ($reward = mysqli_fetch_field($result)) {
                // echo '<th scope="col">' . $reward->name . '</th>';  //get field name for header
                array_push($all_reward, $reward->name);  //save those to array
            }
            // echo '      </tr>
            //         </thead>'; //end tr tag
            echo '<table class="table">
            <thead>
                <tr>
                <th scope="col">Reward</th>
                <th scope="col">Points Required</th>
                <th scope="col">Edit</th>
                <th scope="col">Delete</th>
                </tr>
            </thead>';
    
            //showing all data
            while ($row = mysqli_fetch_array($result)) {
                echo "<tbody>
                        <tr>";
                foreach ($all_reward as $item) {
                    echo '<td>' . $row[$item] . '</td>'; //get items using property value
                }
                echo '<td><i class="fas fa-edit"></i></td>';
                echo '<td><i class="fas fa-trash"></i></td>';
                echo '  </tr>
                    </tbody>';
            }
            echo "</table>";
    ?>

redeem-form.js

$(document).ready(function() {
    $("#add-reward-form").submit(function(e) {
        e.preventDefault();
        $.ajax( {
            url: "add_rewards.php", 
            method: "POST",
            data: $("form").serialize(),
            dataType: "text",
            success: function(strMessage) {
                $("#message").text(strMessage);
                $("#add-reward-form")[0].reset();
                $("#sql-table").load(" #sql-table > *");
            }
        });
        $("#sql-table").load(" #sql-table > *");
    });
    
});

The form works perfectly fine with ajax, and submits to the database without refreshing. But I would like to update the table on my page as well without reloading.

$("#sql-table").load(" #sql-table > *");

This is what I tried. I placed it inside the success function and the submit function but both did not work.

Answer 1

You are mis-using $.load() . It's a shorthand for $.ajax() . The first argument must be a URL. Optional arguments are data and options .

You are passing it a selector, so the request fails. As-is, $("#sql-table").load(" #sql-table > *"); is attempting an AJAX request to the URL /%20#sql-table%20%3E%20* . (!)

Simply change the selector for the PHP file you want to execute:

$("#sql-table").load("tables.php");

Answer 2

How about forcing redeem.php to re-evaluate the PHP div every time a change happens to the inputs?

        <h1>Rewards</h1>
        <script>
            function redrawSQLTable(){
                document.getElementById('sql-table').innerHTML = "<?php include 'tables.php'; ?>"
            }
        </script>
        <form id="add-reward-form" action="" method="POST">
                <label for="inputRewardDescription" class="form-label">Enter Reward Description</label>
                <input type="text" id=inputRewardDescription name="description" class="form-control" required onchange="redrawSQLTable()">
                
                <label for="inputRewardCost" class="form-label">Enter Reward Cost</label>
                <input type="text" id=inputRewardCost name="points" class="form-control" required onchange="redrawSQLTable()">
    
                <button type="submit" class="btn btn-success" id="submit-btn">Save</button>
        </form>  
        <p id="message"></p>
        <div id="sql-table">
            <?php include 'tables.php'; ?>
        </div>