I want to create a sequence of numbers as a string. I have columns "start" and "end" indicating the start and end of the sequence. The desired output is a string with a sequence by 1. See the example below.
df <- data.frame(ID=seq(1:5),
start=seq(2,10,by=2),
end=seq(5,13,by=2),
desired_output_aschar= c("2,3,4,5", "4,5,6,7", "6,7,8,9", "8,9,10,11", "10,11,12,13"))
View(df)
Thank you in advance...
The following solution needs only one *apply
loop.
mapply(function(x, y) paste(x:y, collapse = ","), df$start, df$end)
#[1] "2,3,4,5" "4,5,6,7" "6,7,8,9" "8,9,10,11" "10,11,12,13"
With the new lambdas, same output.
mapply(\(x, y) paste(x:y, collapse = ","), df$start, df$end)
Mapply to call the different seq function, sapply to call the columns
sapply(
data.frame(mapply(seq,df$start,df$end)),
paste0,
collapse=","
)
X1 X2 X3 X4 X5
"2,3,4,5" "4,5,6,7" "6,7,8,9" "8,9,10,11" "10,11,12,13"
Using dplyr
-
library(dplyr)
df %>%
rowwise() %>%
mutate(output = toString(start:end)) %>%
ungroup
# ID start end output
# <int> <dbl> <dbl> <chr>
#1 1 2 5 2, 3, 4, 5
#2 2 4 7 4, 5, 6, 7
#3 3 6 9 6, 7, 8, 9
#4 4 8 11 8, 9, 10, 11
#5 5 10 13 10, 11, 12, 13
We could use map2
from purrr
library(dplyr)
library(purrr)
df %>%
mutate(output = map2_chr(start, end, ~ toString(.x:.y)))
ID start end desired_output_aschar output
1 1 2 5 2,3,4,5 2, 3, 4, 5
2 2 4 7 4,5,6,7 4, 5, 6, 7
3 3 6 9 6,7,8,9 6, 7, 8, 9
4 4 8 11 8,9,10,11 8, 9, 10, 11
5 5 10 13 10,11,12,13 10, 11, 12, 13
A data.table
option
> setDT(df)[, out := toString(seq(start, end)), ID][]
ID start end desired_output_aschar out
1: 1 2 5 2,3,4,5 2, 3, 4, 5
2: 2 4 7 4,5,6,7 4, 5, 6, 7
3: 3 6 9 6,7,8,9 6, 7, 8, 9
4: 4 8 11 8,9,10,11 8, 9, 10, 11
5: 5 10 13 10,11,12,13 10, 11, 12, 13
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